ExamPlay Light Logo
로그인

JEE MAIN - Physics (2022 - 28th June Morning Shift - No. 27)

A telegraph line of length 100 km has a capacity of 0.01 $$\mu$$F/km and it carries an alternating current at 0.5 kilo cycle per second. If minimum impedance is required, then the value of the inductance that needs to be introduced in series is _____________ mH. (if $$\pi$$ = $$\sqrt{10}$$)
답변
100

설명

Total capacitance = 0.01 $$\times$$ 100 = 1 $$\mu$$F

$$\omega$$ = 500 $$\times$$ 2$$\pi$$ = 1000$$\pi$$ rad/s

$$\omega L = {1 \over {\omega C}}$$

$$ \Rightarrow L = {1 \over {{\omega ^2}C}} = {1 \over {{{10}^6}{\pi ^2} \times {{10}^{ - 6}}}} = {1 \over {10}}H$$ = 100 mH

댓글 (0)

댓글을 달려면 로그인하세요
광고
BrainBehindX Inc Logo
©2026; 에 의해 구동 BrainBehindX Inc